MisterWaffles wrote:That's disgusting, Waffles. You are two stinkin' years ahead... I'm sixteen and in Alg. II and I only understand it every now and then, LOL...
Don't worry, Ari. I made horrible grades in Alg I last year. Then my little light bulb clicked on. I'm sure yours will too at some point. Anyone can do anything if they just put their mind to it.
MisterWaffles wrote:Oh. Ok. We just learned that a few lessons ago.
8 ^2/3
Ok. Your numerator will be the power, while the denominator will be the root.
So...First, I suggest getting the rooe of 8. Since the denominator is 3, it would be the cubed rooe of eight. What multiplied by itself three times = 8?
Then, take your answer and make it squared, since the numerator is two. (i.e. "Answer x Answer" would be the same as "Answer^2")
Example Problem:
27 2/3
Cubed root of 27, since the denominator is three.multiplied by itself three times equals 27, so this would be the cubed rt. (i.e. 3 x 3 x 3 = 27)
Then 3^2. (3 x 3)
Which is 9.
Another example...
16 ^1/2
So we get the square root of sixteen, since the denominator is 2. Square root of 16= 4.
Then, 4^1 is just 4.
So the answer is 4.
And yet another...
81^3/4
So we take the 4 root of 81, since 4 is the denominator. What multiplied by itself 4 times is 81? That would be three. So the number is 3.
Then we take 3 cubed ,since the numerator is three.
3 x 3 x 3 = 27.
I could be completely wrong. I just learned this, so anyone more experienced feel free to correct me.
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