Factorization, Algebra II

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Rosendorn
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Tue May 05, 2009 12:16 am
Rosendorn says... · Tue May 05, 2009 12:16 am
(x+ y+ z)(yz+ zx+ xy)- xyz

[x+ (y+ z)][(y+z)x+ yz]- xyz

The next step says it should be:

(y+ z)x^2+ xyz+ (y+z)^2x+ yz(y+ z)- xyz

Thing is, I have no idea how they get "xyz" out of that equation.

Help?
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Snoink
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Thu May 07, 2009 2:33 am
Snoink says... · Thu May 07, 2009 2:33 am
Okay! Since writing out long hand hurts... substitute y+z with p

So: y+z=p

You get:

(x+ p)*(px+ yz)- xyz

Now try to solve it.
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Rosendorn
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Fri May 08, 2009 12:24 am
Rosendorn says... · Fri May 08, 2009 12:24 am
How in the world did I not see that? (Ie- I figured it out. :oops:)

Thanks Snoink!
A writer is a world trapped in a person— Victor Hugo

Ink is blood. Paper is bandages. The wounded press books to their heart to know they're not alone.
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