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Factorization, Algebra II



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Tue May 05, 2009 12:16 am
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Rosendorn says...



(x+ y+ z)(yz+ zx+ xy)- xyz

[x+ (y+ z)][(y+z)x+ yz]- xyz

The next step says it should be:

(y+ z)x^2+ xyz+ (y+z)^2x+ yz(y+ z)- xyz

Thing is, I have no idea how they get "xyz" out of that equation.

Help?
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Ink is blood. Paper is bandages. The wounded press books to their heart to know they're not alone.
  





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Thu May 07, 2009 2:33 am
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Snoink says...



Okay! Since writing out long hand hurts... substitute y+z with p

So: y+z=p

You get:

(x+ p)*(px+ yz)- xyz

Now try to solve it.
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Fri May 08, 2009 12:24 am
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Rosendorn says...



How in the world did I not see that? (Ie- I figured it out. :oops:)

Thanks Snoink!
A writer is a world trapped in a person— Victor Hugo

Ink is blood. Paper is bandages. The wounded press books to their heart to know they're not alone.
  








Daddy Long Legs are more closely related to crabs than spiders and somehow the idea of crablike creatures with spider legs that have escaped the entrappings of the primordial sea and now crawl over land and can walk up and down walls and ceilings creeps me more than I can adequately describe.
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