I am a bit confused about the exponent rules... I just need to simplify these problems.
ab²∗a³b=
(ab)⁴=
x⁵∕y⁴∗(y∕x)³=
Thank you so much for your help!!!
~Winter
Mamillius: Merry or sad shall’t be? Hermione: As merry as you will. Mamillius: A sad tale’s best for winter. I have one Of sprites and goblins. The Winter's Tale
When multiplying exponents, just add them. When dividing them, subtract. When your multiplying the group [the (ab)4 problem] it's just a case of figuring out how many a's need to be multiplied. So, in that problem, it's four.
Get it?
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Thank you so much for your help! I'm still a little confused about multiplying the four a's. Would the answer just be ab⁴? Thanks again for replying!
~WInter
Mamillius: Merry or sad shall’t be? Hermione: As merry as you will. Mamillius: A sad tale’s best for winter. I have one Of sprites and goblins. The Winter's Tale
Oh ok! I get it now. Thank you sooooo much for the help!
Mamillius: Merry or sad shall’t be? Hermione: As merry as you will. Mamillius: A sad tale’s best for winter. I have one Of sprites and goblins. The Winter's Tale
Mamillius: Merry or sad shall’t be? Hermione: As merry as you will. Mamillius: A sad tale’s best for winter. I have one Of sprites and goblins. The Winter's Tale
Since the rule of exponent multiplication is addition, we get:
ab²∗a³b=a¹∙(b²∙a³)∙b¹=a¹∙(a³∙b²)∙b¹=(a¹∙a³)∙(b²∙b¹)=(a¹⁺³)(b²⁺¹)=a⁴b³
The second problem is identical to the first problem: just make sure you understand that everything inside the parentheses is put to the exponent. That is, if I had (ab)³, I would say, (ab)³=(ab)(ab)(ab), by definition of exponentiation. From there, I would follow the procedure I gave you above, changing the parentheses around and use commutativity to get my result.
Best,
Brad
"If I have not seen as far as others, it is because giants were standing on my shoulders." -Hal Abelson
Thank you for writing it out! That makes a lot of sense. So you just write it out as a longer problem so that you can add up the like bases. That's what you were saying, right? At least that's the way that makes the most sense to me. Anyway, thanks again!
-Winter
Mamillius: Merry or sad shall’t be? Hermione: As merry as you will. Mamillius: A sad tale’s best for winter. I have one Of sprites and goblins. The Winter's Tale
Start by looking at the variables individually. Let's start with "a". a^3 multiplied by a, written out, is...
a x a x a x a
That equals a^4.
The same with the Bs means that they're equal to b^3.
(ab)⁴=
Well, this can be written as "(ab) x (ab)". This is a double distributive property thing. First, distribute the a. That makes the second part a^2 x ab. Next, distribute the b. That makes it a^2b x ab^2.
Well, I have to go. Can't do the third one. Sorry.
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