Because I know you all want to help the poor little Algebra 1 student who missed class on Friday and has a quiz tomorrow. *smiles sweetly*
Okey-dokey. Problem one:
A man is now 6 times as old as his son. In 6 years, the father will be 3 times as old as the son will be then. Find their present ages.
^ I know for a fact that no one can be -12/7 years old. So. Any suggestions?
Number 2:
Marie is one-ninth as old as her mother. In 3 years, she will be one-fifth as old as her mother will be then. Find their present ages.
^ Last I checked, people can't have a negative age. But that's what I came out with. O.o
Thanks for taking a look, guys. *dies*
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