Help please!

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I am so not understanding this right now! Does anyone here know how to do Monomials and can help a Lil panda bear not fail her class?!
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Please give example
"Aaloo is potato in urdu, like AAAAAA-loo, or like AAAAA-look such delicious deliciousness."
-Pompadour

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Simplify

(4d^2t^5v^-4)(-5dt^-3v^-1)
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*looks at* Either I don't remember this or haven't learned it yet. Algebra+?
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Algebra 2..., -.-
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....l Agh, only in Geometry. Did you try distributive property and then combining the like terms?
"Aaloo is potato in urdu, like AAAAAA-loo, or like AAAAA-look such delicious deliciousness."
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No... =/ I'm so stressed. I've had bad grades in this class and I feel like crying ... It's ruining my GPA!
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Well try to distribute them and then you can add like terms like that. Don't cry!
"Aaloo is potato in urdu, like AAAAAA-loo, or like AAAAA-look such delicious deliciousness."
-Pompadour

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Thanks for trying to help me! =) It means a lot! I can't help but cry... My college transcript will be ruined if I fail!
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I guess I'm lucky. If I continue in my math classes, I should be in Calculus by 11th grade.
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Go to the web and find one of those sites with math tutors for free, and ask them. You could also search how to do monomials on the Web.
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Here's how I understand it:

(4d^2t^5v^-4)(-5dt^-3v^-1)

1. d^2 multiplied by d^1 = d^3

2. t^5 multiplied by t^-3 = t^2

3. v^-4 multiplied by v^-1 = v^5

Which gives us (4)(-5d^3t^2v^5)

4. 4 multiplied by -5 = -20

Result: (-20)(d^3t^2v^5)

But it's been awhile since I've done Monomials, so don't bet on that answer being right :) If you really need to know, go to Khan Academy. All of Sal Khan's videos are free, and he has everything from 2+2 to how to build your own nuclear reactor. Well, almost.

Hoped this helped :D

-AE-
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AE is pretty close.

(4d^2t^5v^(-4))((-5)dt^(-3)v^(-1)) These negatives actually have a bit more significance than that though. When you have negatives in monomials like this, it means that they're supposed to be on the other side of the 'fraction' basically.

For example, x^2 could be written x^2/1, just like anything could, 2/1 is still 2.

However, if you have x^-1 this is actually saying 1/x as the 'negative power' is telling you to flip it.

So if we translate that we get:

(4d^2t^5)
(v^4)
times
(-5d)
(t^3v^1)

Put that all together in one fraction:
(4d^2t^5*(-5)d)
(v^4*t^3v)

Multiplying bases with powers (x^2*x^4) and you need to ADD the powers. (x^6)

The reason:
Spoiler
If you take x*x and multiply it by x*x*x*x, how many x's do you have?
You have two (x^2) from the first, and four (x^4) from the second.
If we just times these two together, we're using the same method as is already being used to make the 'stack' of x^2.
It looks like this: x*x*x*x*x*x.

Can you tell where the first stack and the second stack were at?

You shouldn't be able to aside from memory, so it becomes x^6 which is how many x's we have total afterwards.


(4d^2t^5*(-5)d)
(v^4*t^3v)

Combine like terms.

4*(-5)=(-20)
d^2*d = d^3
t^5/t^3 = t^2/1 you would have t*t*t/t*t, like terms become one just like 2/2=1
1/v^4*v=1/v^5

Put them where they belong

-20d^3t^2
v^5

That should be your answer.




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It's kind of hard to understand math when it's done with keyboard functions, so here you go!
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