But it's been awhile since I've done Monomials, so don't bet on that answer being right If you really need to know, go to Khan Academy. All of Sal Khan's videos are free, and he has everything from 2+2 to how to build your own nuclear reactor. Well, almost.
Hoped this helped
-AE-
I am a machine, but it's only skin deep. Once you break through the crust of my humanity, you'll find the soft clouds beneath. Just don't squeeze to hard, or I'll disappear.
(4d^2t^5v^(-4))((-5)dt^(-3)v^(-1)) These negatives actually have a bit more significance than that though. When you have negatives in monomials like this, it means that they're supposed to be on the other side of the 'fraction' basically.
For example, x^2 could be written x^2/1, just like anything could, 2/1 is still 2.
However, if you have x^-1 this is actually saying 1/x as the 'negative power' is telling you to flip it.
So if we translate that we get:
(4d^2t^5) (v^4) times (-5d) (t^3v^1)
Put that all together in one fraction: (4d^2t^5*(-5)d) (v^4*t^3v)
Multiplying bases with powers (x^2*x^4) and you need to ADD the powers. (x^6)
The reason:
Spoiler! :
If you take x*x and multiply it by x*x*x*x, how many x's do you have? You have two (x^2) from the first, and four (x^4) from the second. If we just times these two together, we're using the same method as is already being used to make the 'stack' of x^2. It looks like this: x*x*x*x*x*x.
Can you tell where the first stack and the second stack were at?
You shouldn't be able to aside from memory, so it becomes x^6 which is how many x's we have total afterwards.
(4d^2t^5*(-5)d) (v^4*t^3v)
Combine like terms.
4*(-5)=(-20) d^2*d = d^3 t^5/t^3 = t^2/1 you would have t*t*t/t*t, like terms become one just like 2/2=1 1/v^4*v=1/v^5
It's kind of hard to understand math when it's done with keyboard functions, so here you go!
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