z

Young Writers Society


Algebra 2: Quadratic Equations



User avatar
5 Reviews



Gender: None specified
Points: 1090
Reviews: 5
Wed Oct 27, 2010 10:27 pm
Joy Sauce says...



I'm stuck on a word problem, of course. It asks for the dimensions of a rectangle with a perimeter of 66 ft and an area of 216 ft^2. I did the math mentally and got that the sides are 9 and 24, but I must write and solve (using the zero-product property) a quadratic equation in order to get credit; I'm having trouble figuring that out. So, if it can be explained, thank you! :]
  





User avatar
1220 Reviews



Gender: None specified
Points: 72525
Reviews: 1220
Wed Oct 27, 2010 11:44 pm
Kale says...



Ah, don't you just love it when they require you to show your work? I feel your pain, my dear, and so here I am to help!

The quadratic equation would be:

x^2 - 33x + 216 = 0

33 comes from l*w since perimeter is 2lw.

The b term must be negative in order for the equation to equal 0.
- Think what would happen if everything was addition.
- Since we are talking side lengths, you can't have a negative length, so the first and third terms must be positive.

From there, it's just a matter of factoring and finding the zeros. You'll wind up with:

(x - 9)(x - 24) = 0

And so x = 9 and 24, which are your two sides.
Secretly a Kyllorac, sometimes a Murtle.
There are no chickens in Hyrule.
Princessence: A LMS Project
WRFF | KotGR
  





User avatar
5 Reviews



Gender: None specified
Points: 1090
Reviews: 5
Thu Oct 28, 2010 12:08 am
Joy Sauce says...



Ah, yes, that makes sense now. =D Thank you so much!
  








If you don't know it's impossible it's easier to do. And because nobody's done it before, they haven't made up rules to stop anyone doing that again, yet.
— Neil Gaiman