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Factorization, Algebra II



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Tue May 05, 2009 12:16 am
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Rosendorn says...



(x+ y+ z)(yz+ zx+ xy)- xyz

[x+ (y+ z)][(y+z)x+ yz]- xyz

The next step says it should be:

(y+ z)x^2+ xyz+ (y+z)^2x+ yz(y+ z)- xyz

Thing is, I have no idea how they get "xyz" out of that equation.

Help?
A writer is a world trapped in a person— Victor Hugo

Ink is blood. Paper is bandages. The wounded press books to their heart to know they're not alone.
  





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Thu May 07, 2009 2:33 am
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Snoink says...



Okay! Since writing out long hand hurts... substitute y+z with p

So: y+z=p

You get:

(x+ p)*(px+ yz)- xyz

Now try to solve it.
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Fri May 08, 2009 12:24 am
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Rosendorn says...



How in the world did I not see that? (Ie- I figured it out. :oops:)

Thanks Snoink!
A writer is a world trapped in a person— Victor Hugo

Ink is blood. Paper is bandages. The wounded press books to their heart to know they're not alone.
  








Owning our story can be hard but not nearly as difficult as spending our lives running from it. Embracing our vulnerabilities is risky but not nearly as dangerous as giving up on love and belonging and joy—the experiences that make us the most vulnerable. Only when we are brave enough to explore the darkness will we discover the infinite power of our light.
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