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Factorization, Algebra II



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Tue May 05, 2009 12:16 am
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Rosendorn says...



(x+ y+ z)(yz+ zx+ xy)- xyz

[x+ (y+ z)][(y+z)x+ yz]- xyz

The next step says it should be:

(y+ z)x^2+ xyz+ (y+z)^2x+ yz(y+ z)- xyz

Thing is, I have no idea how they get "xyz" out of that equation.

Help?
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Thu May 07, 2009 2:33 am
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Snoink says...



Okay! Since writing out long hand hurts... substitute y+z with p

So: y+z=p

You get:

(x+ p)*(px+ yz)- xyz

Now try to solve it.
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Fri May 08, 2009 12:24 am
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Rosendorn says...



How in the world did I not see that? (Ie- I figured it out. :oops:)

Thanks Snoink!
A writer is a world trapped in a person— Victor Hugo

Ink is blood. Paper is bandages. The wounded press books to their heart to know they're not alone.
  








When you cut pieces out of the truth to avoid looking like a fool, you end up looking like a moron instead.
— Robin Hobb