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Factorization, Algebra II



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Tue May 05, 2009 12:16 am
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Rosendorn says...



(x+ y+ z)(yz+ zx+ xy)- xyz

[x+ (y+ z)][(y+z)x+ yz]- xyz

The next step says it should be:

(y+ z)x^2+ xyz+ (y+z)^2x+ yz(y+ z)- xyz

Thing is, I have no idea how they get "xyz" out of that equation.

Help?
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Thu May 07, 2009 2:33 am
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Snoink says...



Okay! Since writing out long hand hurts... substitute y+z with p

So: y+z=p

You get:

(x+ p)*(px+ yz)- xyz

Now try to solve it.
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Fri May 08, 2009 12:24 am
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Rosendorn says...



How in the world did I not see that? (Ie- I figured it out. :oops:)

Thanks Snoink!
A writer is a world trapped in a person— Victor Hugo

Ink is blood. Paper is bandages. The wounded press books to their heart to know they're not alone.
  








It had a perfectly round door like a porthole, painted green, with a shiny yellow brass knob in the exact middle. The door opened on to a tube-shaped hall like a tunnel: a very comfortable tunnel without smoke, with panelled walls, and floors tiled and carpeted, provided with polished chairs, and lots and lots of pegs for hats and coats—the hobbit was fond of visitors. The tunnel wound on and on, going fairly but not quite straight into the side of the hill —The Hill, as all the people for many miles round called it—and many little round doors opened out of it, first on one side and then on another.
— JRR Tolkien